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 Post subject: "Corduroy", & Joy Division's "Ceremony
PostPosted: Thu Nov 25, 2004 9:11 am 
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Johnny Guitar
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I don't recall Eddie ever mentioning Joy Division/New Order as an influence, but if you listen to 'Ceremony' by Joy Division, as redone by New Order...

The beginning of 'Ceremony', & 'Corduroy' are almost identical in many aspects aswell as other parts of both songs...

really, find 'Ceremony' if you can & listen to it, you'll be surprised if you haven't heard this song, I think Eddie could've really been influenced by this song when writing 'Corduroy', even if he didn't mention it

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 Post subject:
PostPosted: Tue Dec 21, 2004 12:44 pm 
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Instead of the E going up to the C root, it stays on A. It's similar. Not exactly an influential riff. E C A is one of the canonized rock progressions.

New Order does it more than Joy Division did. JD played this wicked wall of sound in their opening, New Order cashed in on Ceremony and made a single out of it. Somewhere in all of this is 'talent'.

Still looking...


(Just my opinion.)

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 Post subject:
PostPosted: Tue Dec 21, 2004 3:39 pm 
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CommonWord wrote:
Instead of the E going up to the C root, it stays on A. It's similar. Not exactly an influential riff. E C A is one of the canonized rock progressions.

Not to disagree, but....



cos2(t) + sin2(t) = 1

sin2(t)
1 + tan2(t) = 1 + ----------
cos2(t)

cos2(t)+sin2(t)
= -----------------
cos2(t)


1
= ----------- = sec2(t)
cos2(t)

Analogous :

1 + cotan2(t) = 1/ sin2(t) = csc2(t)

Image

sin2 (pi/3) = sqrt( 1 - cos2 (pi/3)) = sqrt(3)/2

So, sin(pi/3) = sqrt(3)/2 and cos(pi/3) = 1/2.

Image

So in the final analysis you can see how people might get the wrong idea about the chord structures.


Last edited by Buggy on Wed Dec 22, 2004 1:37 am, edited 1 time in total.

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 Post subject:
PostPosted: Tue Dec 21, 2004 3:46 pm 
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The Decider
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Buggy wrote:
CommonWord wrote:
Instead of the E going up to the C root, it stays on A. It's similar. Not exactly an influential riff. E C A is one of the canonized rock progressions.

Not to disagree, but....



cos2(t) + sin2(t) = 1

sin2(t)
1 + tan2(t) = 1 + ----------
cos2(t)

cos2(t)+sin2(t)
= -----------------
cos2(t)


1
= ----------- = sec2(t)
cos2(t)

Analogous :

1 + cotan2(t) = 1/ sin2(t) = csc2(t)

Image

sin2 (pi/3) = sqrt( 1 - cos2 (pi/3)) = sqrt(3)/2

So, sin(pi/3) = sqrt(3)/2 and cos(pi/3) = 1/2.

Image

So in the final analysis you can see how people might get the wrong idea about the chrod structures.


How I wish I could make this my sig.

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 Post subject:
PostPosted: Tue Dec 21, 2004 11:52 pm 
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Johnny Guitar
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Joined: Sun Oct 17, 2004 7:20 am
Posts: 286
Buggy wrote:
CommonWord wrote:
Instead of the E going up to the C root, it stays on A. It's similar. Not exactly an influential riff. E C A is one of the canonized rock progressions.

Not to disagree, but....



cos2(t) + sin2(t) = 1

sin2(t)
1 + tan2(t) = 1 + ----------
cos2(t)

cos2(t)+sin2(t)
= -----------------
cos2(t)


1
= ----------- = sec2(t)
cos2(t)

Analogous :

1 + cotan2(t) = 1/ sin2(t) = csc2(t)

Image

sin2 (pi/3) = sqrt( 1 - cos2 (pi/3)) = sqrt(3)/2

So, sin(pi/3) = sqrt(3)/2 and cos(pi/3) = 1/2.

Image

So in the final analysis you can see how people might get the wrong idea about the chrod structures.


You are my hero for the next half month, on this message board at least. And why am I not giving you a Christmas gift? :P

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 Post subject:
PostPosted: Wed Dec 22, 2004 12:21 am 
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I though we Ron Artested your dumbass.

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 Post subject:
PostPosted: Wed Dec 22, 2004 12:32 am 
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Johnny Guitar
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Joined: Sun Oct 17, 2004 1:52 am
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Buggy wrote:
CommonWord wrote:
Instead of the E going up to the C root, it stays on A. It's similar. Not exactly an influential riff. E C A is one of the canonized rock progressions.

Not to disagree, but....



cos2(t) + sin2(t) = 1

sin2(t)
1 + tan2(t) = 1 + ----------
cos2(t)

cos2(t)+sin2(t)
= -----------------
cos2(t)


1
= ----------- = sec2(t)
cos2(t)

Analogous :

1 + cotan2(t) = 1/ sin2(t) = csc2(t)

Image

sin2 (pi/3) = sqrt( 1 - cos2 (pi/3)) = sqrt(3)/2

So, sin(pi/3) = sqrt(3)/2 and cos(pi/3) = 1/2.

Image

So in the final analysis you can see how people might get the wrong idea about the chrod structures.


A late contender for post of the year!
:D

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 Post subject:
PostPosted: Wed Dec 22, 2004 5:11 am 
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Force of Nature
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Joined: Tue Oct 19, 2004 2:39 am
Posts: 301
Buggy wrote:
CommonWord wrote:
Instead of the E going up to the C root, it stays on A. It's similar. Not exactly an influential riff. E C A is one of the canonized rock progressions.

Not to disagree, but....



cos2(t) + sin2(t) = 1

sin2(t)
1 + tan2(t) = 1 + ----------
cos2(t)

cos2(t)+sin2(t)
= -----------------
cos2(t)


1
= ----------- = sec2(t)
cos2(t)

Analogous :

1 + cotan2(t) = 1/ sin2(t) = csc2(t)

Image

sin2 (pi/3) = sqrt( 1 - cos2 (pi/3)) = sqrt(3)/2

So, sin(pi/3) = sqrt(3)/2 and cos(pi/3) = 1/2.

Image

So in the final analysis you can see how people might get the wrong idea about the chord structures.


*looks at math*
*looks at posts*

Wow.


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 Post subject:
PostPosted: Wed Dec 22, 2004 10:28 am 
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Joined: Mon Dec 13, 2004 7:25 am
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Location: winnipeg manitoba canada
Quote:
I don't recall Eddie ever mentioning Joy Division/New Order as an influence, but if you listen to 'Ceremony' by Joy Division, as redone by New Order...


i can't believe i just read this. i only just got into joy division and new order in the last couple months and as soon as i heard the new order version of ceremony the first thing that came to my mind was corduroy. blast you for mentioning it first! no just curse my laziness for not doing so

on a side note did anyone here notice a similarity in eddie and ian's voices? its not so much that they sound alike but they both sound very masculine


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 Post subject:
PostPosted: Wed Dec 22, 2004 6:12 pm 
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Joined: Mon Oct 18, 2004 9:39 pm
Posts: 72
Location: Pittsburgh, PA
Buggy wrote:



cos2(t) + sin2(t) = 1

sin2(t)
1 + tan2(t) = 1 + ----------
cos2(t)

cos2(t)+sin2(t)
= -----------------
cos2(t)


1
= ----------- = sec2(t)
cos2(t)

Analogous :

1 + cotan2(t) = 1/ sin2(t) = csc2(t)

Image

sin2 (pi/3) = sqrt( 1 - cos2 (pi/3)) = sqrt(3)/2

So, sin(pi/3) = sqrt(3)/2 and cos(pi/3) = 1/2.

Image

So in the final analysis you can see how people might get the wrong idea about the chord structures.




that made my day

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